Article "Certificato del tesoro zero-coupon" in Italian Wikipedia has 9.3 points for quality (as of November 1, 2023). The article contains 1 references and 5 sections.
Since the creation of article "Certificato del tesoro zero-coupon", its content was written by 24 registered users of Italian Wikipedia and edited by 24 registered Wikipedia users in all languages.
The article is cited 16 times in Italian Wikipedia and cited 16 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from November 1, 2023 (including revision history and pageviews for previous years).
| Best Rank | Italian: #11637 11.2011 |
Global: #304141 11.2011 |
| Best Rank | Italian: #1688 03.2005 |
Global: #110203 03.2005 |
On 30 May 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: Feast of Corpus Christi, YouTube, Vincent Kompany, Hansi Flick, UEFA Europa Conference League, deaths in 2024, ChatGPT, Olympiacos F.C., Furiosa: A Mad Max Saga, UEFA Euro 2024.
In Italian Wikipedia the most popular articles on that day were: Paolo Villaggio, Giacomo Matteotti, Hermodice carunculata, Agostino Di Bartolomei, Com'è umano lui!, Stevan Jovetić, Olympiakos Syndesmos Filathlōn Peiraiōs, UEFA Europa Conference League, Discorso di Giacomo Matteotti del 30 maggio 1924, Skyfall.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2023. When calculating current popularity and AI of articles data from October 2023 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(2.85+0.61+0+21.74+21.11)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
